Longest Common Subsequence: Difference between revisions
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Currently no algorithms in our database for the given problem. | Currently no algorithms in our database for the given problem. | ||
== Time Complexity | == Time Complexity Graph == | ||
[[File:Longest Common Subsequence - Time.png|1000px]] | [[File:Longest Common Subsequence - Time.png|1000px]] | ||
== Space Complexity | == Space Complexity Graph == | ||
[[File:Longest Common Subsequence - Space.png|1000px]] | [[File:Longest Common Subsequence - Space.png|1000px]] | ||
== Pareto | == Pareto Frontier Improvements Graph == | ||
[[File:Longest Common Subsequence - Pareto Frontier.png|1000px]] | [[File:Longest Common Subsequence - Pareto Frontier.png|1000px]] |
Revision as of 13:03, 15 February 2023
Description
The longest common subsequence (LCS) problem is the problem of finding the longest subsequence common to all sequences in a set of sequences (often just two sequences).
Related Problems
Subproblem: Longest Common Substring with don't cares
Parameters
$n$: length of the longer input string
$m$: length of the shorter input string
$r$: length of the LCS
$s$: size of the alphabet
$p$: the number of dominant matches (AKA number of minimal candidates), i.e. the total number of ordered pairs of positions at which the two sequences match
Table of Algorithms
Currently no algorithms in our database for the given problem.
Time Complexity Graph
Space Complexity Graph
Pareto Frontier Improvements Graph
Reductions FROM Problem
Problem | Implication | Year | Citation | Reduction |
---|---|---|---|---|
UOV | If: to-time: $O((nm)^{({1}-\epsilon)})$, where $|x| = O(nd)$ and $|y| = O(md)$ Then: from-time: $O((nm)^{({1}-\epsilon/{2})})$ |
2015 | https://arxiv.org/pdf/1502.01063.pdf | link |
References/Citation
https://link.springer.com/chapter/10.1007/978-3-662-43948-7_4