K-SAT: Difference between revisions

From Algorithm Wiki
Jump to navigation Jump to search
(Created page with "{{DISPLAYTITLE:k-SAT (Boolean Satisfiability)}} == Description == k-SAT restricts the boolean formula to CNF with (at most) k literals per clause == Related Problems == Generalizations: Conjunctive Normal Form SAT Subproblem: 2SAT, 3SAT, 4SAT Related: SAT, Disjunctive Normal Form SAT, 1-in-3SAT, Monotone 1-in-3SAT, Monotone Not-Exactly-1-in-3SAT, All-Equal-SAT, Not-All-Equal 3-SAT (NAE 3SAT), Monotone Not-All-Equal 3...")
 
No edit summary
Line 14: Line 14:
== Parameters ==  
== Parameters ==  


<pre>n: number of variables
n: number of variables
c: dependant on k</pre>
 
c: dependant on k


== Table of Algorithms ==  
== Table of Algorithms ==  

Revision as of 12:03, 15 February 2023

Description

k-SAT restricts the boolean formula to CNF with (at most) k literals per clause

Related Problems

Generalizations: Conjunctive Normal Form SAT

Subproblem: 2SAT, 3SAT, 4SAT

Related: SAT, Disjunctive Normal Form SAT, 1-in-3SAT, Monotone 1-in-3SAT, Monotone Not-Exactly-1-in-3SAT, All-Equal-SAT, Not-All-Equal 3-SAT (NAE 3SAT), Monotone Not-All-Equal 3-SAT (Monotone NAE 3SAT), 3SAT, 3SAT-5, 4SAT, Monotone 3SAT, XOR-SAT, Horn SAT, Dual-Horn SAT, Renamable Horn, MaxSAT

Parameters

n: number of variables

c: dependant on k

Table of Algorithms

Name Year Time Space Approximation Factor Model Reference
Paturi, Pudlák, Saks, Zane (PPSZ) 2005 O^*({2}^{n-cn/k}) $O(kn)$ Exact Randomized Time

Reductions TO Problem

Problem Implication Year Citation Reduction
Subset Sum assume: SETH
then: for any $\epsilon > {0}$ there exists a $\delta > {0}$ such that Subset Sum is not in time $O(T^{1-\epsilon}{2}^{\delta n})$, and $k$-Sum is not in time $O(T^{1-\epsilon}n^{\delta k})$
2022 https://dl.acm.org/doi/full/10.1145/3450524 link